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The torque experienced by a given current carrying loop in a uniform magnetic field $\vec{B}$ given by $B_{0} (\vec{i} - \vec{j})$ would have magnitude

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$\sqrt{2} B_{0} a^{2} I$

zero

$2 B_{0} a^{2} I$

$B_{0} a^{2} I$

answer is B.

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Detailed Solution

$\vec{M} = I a^{2} [- \hat{i} + \hat{j}], B = B_{0} (\vec{i} - \vec{j}) \vec{τ} = \vec{M} \times \vec{B} Solve to get τ = 0$

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