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Q.

The torque of force F=2i3j+4k newton acting at the point r=3i+2j+3k metre about the origin is

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a

6i+6j12k

b

17i6j13k

c

6i6j+12k

d

17i+6j+13k

answer is B.

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Detailed Solution

F=2i3j+4k

r=3i+2j+3k

τ=r×F×=|ijk323234|

=i(8+9)j(126)+k(94)

=17i^6j^13k^

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