The total change in the oxidation state of manganese involved in the reaction of a KMnO4 and potassium iodide in the acidic medium is

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The total change in the oxidation state of manganese involved in the reaction of a KMnO₄ and potassium iodide in the acidic medium is

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answer is 5.

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Detailed Solution

KMnO4 + KI in Acidic Medium

The reaction of KMnO₄ and potassium iodide (KI) in acidic medium can be represented as follows:

MnO₄⁻ + I⁻ + H⁺ → Mn²⁺ + I₂ + H₂O

In this reaction, KMnO₄ acts as an oxidizing agent, while KI acts as a reducing agent. The oxidation state of manganese changes from +7 in KMnO₄ to +2 in Mn²⁺, which is a reduction of 5 units.

Therefore, the total change in the oxidation state of manganese involved in the reaction is 5.

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