The total concentration of dissolved particles inside red blood cells is approximately 0.30 M and the membrane surrounding the cells is semipermeable. What would be the osmotic pressure (in atmosphere) inside the cells become if the cell were removed from the blood plasma and placed in pure water at 298 K?

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2.34 atm

0.74 atm

7.34 atm

1.78 atm

answer is A.

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Detailed Solution

The osmotic pressure (in atmosphere) inside the cells become if the cell were removed from the blood plasma and placed in pure water at 298 K.

$π = CST = 0.3 \times 0.0821 \times 298 = 7.34 atm$

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