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Q.

The total energy of a particle executing SHM is 48 Joule. Then find its potential energy when its displacement is half of the amplitude.

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a

24 J      

b

16 J      

c

36 J        

d

12 J

answer is D.

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Detailed Solution

E = Total Energy  =12  mω2  A2
∴    12  mω2 =E/ A2
Now,   U = Potential Energy   12  mω2 x2
When  x=A2,      U=EA2  ×   A22=E4=484  J=12J.

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