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The total internal energy of one mole of rigid diatomic gas is

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$\frac{7}{2} R T$

$\frac{3}{2} R T$

$\frac{9}{2} R T$

$\frac{5}{2} R T$

answer is C.

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Detailed Solution

A rigid diatomic molecule has 5 degrees of freedom total internal energy of one mole of rigid diatomic gas is

$U = \frac{5}{2} k_{B} T \times N_{A} = \frac{5}{2} R T (∵ R = k_{B} N_{A})$

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