The total mechanical energy of a spring-mass system in simple harmonic motion is $E = \frac{1}{2} m ω^{2} A^{2} .$ Suppose the oscillating particle is replaced by another particle of double the mass while the amplitude A remains the same. The new mechanical energy will

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become E/2

remain E

become 2E

become $\sqrt{2} E$

answer is D.

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Detailed Solution

The total energy is the maximum potential energy stored in the spring at the extreme position of the SHM, if the body is replaced by a body of double the mass the potential energy remains same.

So the total energy in this case remains E.

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