We have

$75600=2^4\cdot 3^3\cdot 5^2\cdot 7$

The total number of ways of selecting some or all out of four 2's, three two 5's and one 7's

$=(4+1)(3+1)(2+1)(1+1)-1=119.$

But, this includes the given number itself. Therefore, the 

required number of proper factors is 118.