The total number of coordination isomers possible for the following compounds respectively are :
$\begin{array}{l} [Co (en)_{3}] [Cr {(C_{2} O_{4})}_{3}] \\ [Cu {({NH}_{3})}_{4}] [{CuCl}_{4}] \\ [Ni (en)_{3}] [Co {({NO}_{2})}_{6}] \end{array}$

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4, 4, 4

2, 2, 2

2, 2, 4

4, 2,3

answer is D.

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Detailed Solution

$\begin{array}{l} [Co (en)_{3}] [Cr {(C_{2} O_{4})}_{3}], [Co (C_{2} O_{4}) (en)_{2}] [Cr {(C_{2} O_{4})}_{2} (en)], \\ [Cr (C_{2} O_{4}) (en)_{2}] [Co {(C_{2} O_{4})}_{2} (en)], \\ [Cr (en)_{3}] [Co {(C_{2} O_{4})}_{3}], Total coordination isomers = 4 \\ [Cu {({NH}_{3})}_{4}] [{CuCl}_{4}], [CuCl {({NH}_{3})}_{3}] [{CuCl}_{3} ({NH}_{3})] \end{array}$
Total coordination isomers = 2
$\begin{aligned} [Ni (en)_{3}] [Co {({NO}_{2})}_{6}], [Ni {({NO}_{2})}_{2} (en)_{2}] [Co {({NO}_{2})}_{4} (en)] \\ [Co {({NO}_{2})}_{2} (en)_{2}] [Ni {({NO}_{2})}_{4} (en)], [Co (en)_{3}] [Ni {({NO}_{2})}_{6}] \end{aligned}$
Total no. of coordination isomers = 4