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Q.

The total number of electrons present in 18 mL water (density 1 g/mL) is

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a

$6.023 \times 10^{25}$

b

$6.023 \times 10^{24}$

c

$6.023 \times 10^{21}$

d

$6.023 \times 10^{23}$

answer is B.

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Detailed Solution

.each water molecule has 10 electrons,18 grams has one mole of molecules, therefore 18 grams has 10N electrons

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The total number of electrons present in 18 mL water (density 1 g/mL) is