The total number of Faradays required to oxidize the following separately
I) 1 mol of $S_{2} {O_{3}}^{2 -}$ in acid medium
II) 1 Equivalent of $S_{2} {O_{3}}^{2 -}$ in neutral medium
III) 1 mol of $S_{2} {O_{3}}^{2 -}$ in basic medium

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answer is 10.

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Detailed Solution

$(1) S_{2} O_{3}^{2 -} \to \frac{1}{2} S_{4} O_{6}^{2 -} + e^{-} [1 F]$

$(2) S_{2} O_{3}^{2 -} + 5 H_{2} O \to 2 H S O_{0}^{Θ} + 8 H^{Θ} + 8 e^{-}$

$(3) S_{2} O_{3}^{2 -} + 10 \overset{Θ}{O} H \to 2 S O_{4}^{2 -} + 5 H_{2} O + 8 e^{-}$

$[1 m o l = 8 F]$

Total Faradays in $(1) (2) & (3) = 1 + 1 + 8 = 10 F$

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