The Total number of gm-molecules of ${\mathrm{SO}}_2{\mathrm{Cl}}_2$ in $13.5\mathrm{g}$ of sulphuryl chloride is 

Molecular weight of ${\mathrm{SO}}_2{\mathrm{Cl}}_2$

$=32+32+2\times 35.5=135\mathrm{gm}$

$\because 135\mathrm{gm}\text{ of }{\mathrm{SO}}_2{\mathrm{Cl}}_2=1\mathrm{gm}$ molecule

$\therefore \mathrm{1.3.5}\mathrm{gm}$ of ${\mathrm{SO}}_2{\mathrm{Cl}}_2=\frac{1}{135}\times 13.5=0.1$