The total number of gram-molecules of SO₂Cl₂ in 13.5 g of sulphuryl chloride is

$\text{ Molecular weight of }{\mathrm{SO}}_2{\mathrm{Cl}}_2=32+32+2\times 35.5=135\mathrm{g}$

$\because 135\mathrm{g}\text{ of }{\mathrm{SO}}_2{\mathrm{Cl}}_2=1\mathrm{g}\text{ molecule }$

$\therefore 13.5\mathrm{g}\text{ of }{\mathrm{SO}}_2{\mathrm{Cl}}_2=\frac{1}{135}\times 13.5=0.1$.