The total number of possible coordination isomer for the given compound $\left[\mathrm{Pt}{\left({\mathrm{NH}}_3\right)}_4{\mathrm{Cl}}_2\right]\left[{\mathrm{PtCl}}_4\right]$ is

$\stackrel{ +\mathrm{IV} }{\left[{\mathrm{PtCl}}_2{\left({\mathrm{NH}}_3\right)}_4\right]}\left[{\mathrm{PtCl}}_4\right];\stackrel{2+ \mathrm{II} 2+\mathrm{IV} }{\left[{\mathrm{PtCl}}_3{\left({\mathrm{NH}}_3\right)}_3\right]}\stackrel{+ +\mathrm{II} - }{\left[{\mathrm{PtCl}}_3\left({\mathrm{NH}}_3\right)\right]}$

$\stackrel{+\mathrm{II} +}{\left[\mathrm{PtCl}{\left({\mathrm{NH}}_3\right)}_3\right]}\stackrel{+ IV -}{\left[{\mathrm{PtCl}}_5\left({\mathrm{NH}}_3\right)\right]};\stackrel{\mathrm{II} 2+}{\left[\mathrm{Pt}{\left({\mathrm{NH}}_3\right)}_4\right]}\stackrel{\mathrm{IV} 2-}{\left[{\mathrm{PtCl}}_6\right]}$