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The total number of turns and cross-section area in a solenoid is fixed. However its length $L$ is varied by adjusting the separation between windings. The inductance of solenoid will be proportional to

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$L$

$L^{2}$

$\frac{1}{L}$

$\frac{1}{L^{2}}$

answer is A.

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Detailed Solution

For a solenoid, self inductance is given as

$L_{self} = N \times A \times μ_{0} (\frac{N}{L}) ∴ L_{self} \propto \frac{1}{L}$

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