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The total pressure of a mixture of $6.4 g m s$ of oxygen and $5.6 g m$ of nitrogen present in 2 litres vessel is $1200 m m H g .$ What is the partial pressure of nitrogen in mmHg?

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answer is 600.

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Detailed Solution

$P_{N_{2}} = X_{N_{2}} \times$ total pressure $P_{N_{2}} = [\frac{\frac{5.6}{28}}{\frac{6.4}{32} \times \frac{5.6}{28}}] \times 1200 \Rightarrow P_{N_{2}} = 600$

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