The total sum of oxidation states of sulphur in $S_8,S{F}_2,H_{2}S$ is

It is given to find out the oxidation state of sulfur in S₈, SF₂ and H₂S.

Oxidation state of sulfur in S₈ is 0 as sulfur is in its elemental state.

Oxidation state  of sulfur in SF₂  is +1 :

Let oxidation state of sulfur be x

As fluorine is electronegative, it shows an oxidation state of -1

Overall charge is zero

x + 2 (-1) = 0

x = +2

Oxidation state of sulfur in H₂S is -2 : 

Let oxidation state of sulfur be x

Hydrogen shows an oxidation state of +1

Overall charge is zero

2 (+1) + x = 0

x = -2

The total sum of oxidation states of sulphur in $S_8,S{F}_2,H_{2}S$ = 0 +2 -2

                                                                                                    =0