The total surface area of a hollow cylinder which is open from both sides is 4620 $c m^{2}$ , the area of the base ring is 115.5 $c m^{2}$ and height 7 cm. Find the thickness of the cylinder.

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0.268

0.390

0.368

0.295

answer is C.

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Detailed Solution

Given that,
The total surface area of a hollow cylinder = 4620

c m^{2}

Area of base ring = 115.5

c m^{2}

height =7cm
The total surface area of a hollow cylinder,

⇒ 2 π R h + 2 π r h + 2 π (R 2 − r 2)

The area of the base,

⇒ 115.5 = π (R 2 − r 2) ⇒ 115.5 = 227 (R − r) (R + r) ⇒ 1474 = (R − r) (R + r) … … (1)

The total surface area of the hollow cylinder,
Question Image

We substitute the value

(R + r) = 3994

⇒ 1474 = (R − r) × 3994 ⇒ (R − r) = 399147 ⇒ (R − r) = 0.368

Thus, the thickness of the cylinder will be

0.368

.
Therefore, the correct option is 3.

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