The total surface area of a hollow metal cylinder that is open at both ends and has an external radius of 8 cm and a height of 10 cm is 338 $cm 2$ . If we take r to be the inner radius and get an equation in r and use it to get the thickness of the metal in the cylinder. What will be the thickness?

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4cm

3cm

5cm

2cm

answer is B.

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Detailed Solution

Given that,
The total surface area of a hollow metal cylinder=

338 c m 2.

External radius

= 8 cm

Height

= 10 c m

The total surface area of the hollow cylinder,

2 π R h + 2 π r h + 2 π (R 2 − r 2)

The thickness will be,

⇒ R − r = 8 − 5 = 3 c m

Thus, the thickness will be 3cm.
Therefore, the correct option is 2.

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