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Q.

The transformed equation of x36x2+5x+8=0  by eliminating second term is

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a

x35x+2=0

b

x37x+2=0

c

x3+7x+2=0

d

x3+5x+2=0

answer is B.

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Detailed Solution

Question Image

3h6=0

3h=6

h=2

To eliminate second term

Question Image

So transformed equation is x37x+2=0 .

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