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Q.

The transverse displacement of a string fixed at both ends is given by y,x  are in meter y=0.06sin2πx3cos120πt  and t  in sec the length of string is 1.5 m and its mass is 3×103kg . Find amplitude at point x=0.5m.

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a

0.02 m

b

0.052 m

c

0.4 m

d

0.6 m 

answer is B.

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Detailed Solution

Displacement is maximum when  cos120πt=1 Hence the amplitude =0.06sin2πx3   At x=0.5m A=0.06sin2π3×0.5 =0.052m

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