Q.

The treatment of an aqueous solution of 1.87g of Cu(NO3)2 with excess KI results in a brown 
solution along with the formation of a precipitate.H2S Passing through this brown solution gives 
another precipitate x. the amount of X (in g) is……
[Given atomic mass of H=1,N=14 O=16, S=32 K=39 Cu=63 I=127] 
 

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answer is 0.16.

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Detailed Solution

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KI3+H2SS+KI+2HI

0.005mole         0.005mole                        0.005×32                        0.160                       0.16gofsulpur

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