The treatment of phenol with phthalic anhydride in the presence of concentrated $H_{2} {SO}_{4}$ produces

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aspirin

methyl red

methyl orange

phenolphthalein

answer is D.

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Detailed Solution

The treatment of phenol with phthalic anhydride in the presence of concentrated $H_{2} {SO}_{4}$ produces phenolphthalein

One molecule of phthalic anhydride combines with two molecules of phenol to create a molecule of phenolphthalein in the presence of concentrated sulfuric acid. The process results in the loss of one water molecule. This is a condensation reaction as a result.

Hence option D is correct

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