The treatment of ${\mathrm{CH}}_3\mathrm{CH}={\mathrm{CHCH}}_3$ with ${\mathrm{NaIO}}_4$ or boiling ${\mathrm{KMnO}}_4$produces

${\mathrm{CH}}_3\mathrm{CH}={\mathrm{CHCH}}_3+{\mathrm{NaIO}}_4\to 2\mathrm{CHCOOH}$

Alkene undergoes oxidation in the presence of an oxidising agent, such as boiling ${\mathrm{KMnO}}_4$, to produce diol, which then undergoes additional oxidation to produce aldehyde or ketone.
When these aldehydes are further oxidised, a carboxylic acid is created. As the alkene in this instance is symmetrical, just carboxylic acid is produced.