The triangle drawn in the given figure is similar to which of the following triangles?

In each of the triangles in the alternatives, the lengths of two sides and an internal angle are known. Thus, the Side-Angle-Side similarity postulate needs to be applied here. 

According to the postulate, two triangles are similar if two pairs of corresponding sides are proportional and the included angles are equal.

Comparing the given ΔABC with ΔUVW shown in alternative D:

$$\begin{gathered} \frac{AB}{VU}=\frac{2.4}{3.6}=\frac{2}{3} \\ \frac{AC}{VW}=\frac{4.6}{6.9}=\frac{2}{3} \\ \therefore \frac{AB}{VU}=\frac{AC}{VW}=\frac{2}{3} \end{gathered}$$

In ΔABC, the angle included by sides AB and AC is ∠A, which measures z°.

In ΔUVW, the angle included by sides VU and VW is ∠V, which also measures z°.

Thus, ∠A = ∠V = z°

Thus, by the Side-Angle-Side similarity postulate, ΔABC is similar to ΔVUW.