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The triangular side walls of a flyover have been used for advertisements. The sides of the walls are 122 m, 22 m and 120 m (see Fig.). The advertisements yield an earning of ₹ 5000 per m2 per year. A company hired one of its walls for 3 months. How much rent did it pay?

The triangular side walls of a flyover have been used for advertisements. The  sides of the walls are 122m, 22m, and 120m. The advertisements yield an  earning of ₹ 5000 per m2

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detailed solution

Correct option is A

We know that, 

The Heron's formula for calculating the area of the triangle,

Area of triangle = s (s - a) (s - b) (s -c)

where, s is the semi-perimeter = half of the perimeter

and  a, b and c are the sides of the triangle 

Triangular sides of walls are, a = 122 m, b = 22 m, c = 120 m

Thus, Semi-perimeter 

s = (a + b + c)/2

= (122 + 22 + 120)/2

= 264/2

= 132 m

Area of a triangular wall = 132 (132 -122) (132-22) (132 -120)

132 × 10 × 110 × 12

= 1320 m

Given that, 

Rent of 1 m2 area per year = ₹ 5000

Rent of 1 m2 area per month = ₹ 5000/12

Rent of 1320 marea for 3 months =  (5000/12) × 3 ×1320

= ₹ 1650000

Hence, the company paid ₹ 16,50,000 as rent.

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detailed solution

Correct answer is 1

We know that, 

The Heron's formula for calculating the area of the triangle,

Area of triangle = s (s - a) (s - b) (s -c)

where, s is the semi-perimeter = half of the perimeter

and  a, b and c are the sides of the triangle 

Triangular sides of walls are, a = 122 m, b = 22 m, c = 120 m

Thus, Semi-perimeter 

s = (a + b + c)/2

= (122 + 22 + 120)/2

= 264/2

= 132 m

Area of a triangular wall = 132 (132 -122) (132-22) (132 -120)

132 × 10 × 110 × 12

= 1320 m

Given that, 

Rent of 1 m2 area per year = ₹ 5000

Rent of 1 m2 area per month = ₹ 5000/12

Rent of 1320 marea for 3 months =  (5000/12) × 3 ×1320

= ₹ 1650000

Hence, the company paid ₹ 16,50,000 as rent.

Talk to our academic expert!

+91

Are you a Sri Chaitanya student?

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