The true statement of acids of phosphorus $H_{3} P O_{2}, H_{3} P O_{3}$ and $H_{3} P O_{4}$ is

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All of them are reducing in nature

All of them are tribasic acids

The order of their acidity is $H subscript 3 P O subscript 2 greater than H subscript 3 P O subscript 3 greater than H subscript 3 P O subscript 4$ $H_{3} P O_{4} > H_{3} P O_{3} > H_{3} P O_{2}$

The hybridization of phosphorus is $S P^{3}$ in all the three

answer is D.

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Detailed Solution

Order of acidity is $H subscript 3 P O subscript 4 greater than H subscript 3 P O subscript 3 greater than H subscript 3 P O subscript 2$

$H_{3} P O_{4}$ is not a reducing agent

Only $H_{3} P O_{4}$ is a tribasic acid

In all three phosphorus is tetrahedral geometry

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