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Q.

The two coherent sources of equal intensity produce maximum intensity of 100 units at a point. If the intensity of one of the sources is reduced by 50% by reducing its width then the intensity of light at the same point will be

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a

89

b

67

c

90

d

72.85

answer is D.

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Detailed Solution

First case $I_{1} = I_{2} = 1, I_{m a x 1} = (\sqrt{1} + \sqrt{1})^{2} = 4$
For second case
$\begin{array}{l} I_{1} = \frac{1}{2} = 0 .5, I_{2} = 1, I_{m a x 2} = (\sqrt{0 .5} + \sqrt{1})^{2} = 2 .91 \\ \frac{I_{m a x 2}}{I_{m a x 1}} = \frac{2 .91}{4} \Rightarrow \frac{I_{m a x 2}}{100} = 0 .7285 \Rightarrow I_{m a x 2} = 72 .85 \end{array}$

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