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Q.

The two consecutive positive odd numbers’ product is 195. Find the numbers.

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a

25, 24

b

12, 13

c

15, 16

d

13, 15

answer is D.

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Detailed Solution

Concept- Assuming numbers as some variables. Now frame the equation using the condition given in the question and solve it . We can also assume the numbers be x and x+2. In this case we will get a different quadratic equation but the end result will be the same.
Let the two positive consecutive odd numbers be

x - 1 and x + 1 = 195 .

(x - 1) (x + 1) = 195

(x - 4) (x + a) = x^{2} + a^{2}

x^{2} - 1 = 195

x^{2} = 195

x = \pm \sqrt{196}

x = \pm 14

Now we will consider only positive integers. So we will ignore negative values.

x = 14 is the valid solution .

But we have to consider only positive integers, so we will ignore negative values. x=14 is the valid solution.

x - 1 = 13

and

x + 1 = 15

Therefore our numbers are 13 and 15.
Hence, the correct option is 4.

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