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The two diagonally opposite vertices of a square are (6, 6) and (0, 0). Find the point which lies on X-axis.

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(6, 0)

(0, 6)

(6, 6)

None

answer is A.

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Detailed Solution

Our square OABC has equal sides, and we are aware of this.
Therefore,

OA = AB = BC = OC

.... (Square Sides)
Question Image

By distance formula the length of AB can be given as,,

AB = \sqrt{(6 - x)^{2} + (0 - 6)^{2}}

6 = \sqrt{(6 - x)^{2} + (0 - 6)^{2}}

On squaring both sides,

36 = (6 - x)^{2} + 36

x = 6

So, the x-axis point can be given as

A = (6, 0)

.
Thus, option 1 is correct.

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