The two ends of a metal rod are maintained at temperatures 100°C and 110°C The rate of heat flow in the rod is found to be 4.0 J/s. If the ends are maintained at temperatures 200°C and 210°C, the rate of heat flow will be :

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16.81/s

8.0J/s

4.0J/s

44.0J/s

answer is C.

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Detailed Solution

Rate of heat flow $\infty$ temperature difference between two ends $\Rightarrow \frac{dQ}{dt} \infty (T_{2} - T_{1})$
Here temperature difference in both case is same (i.e.,10⁰C). So, rate of heat flow will also be same.
So, $\frac{dQ}{dt} = 4 J / s .$

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