The type of hybrid orbitals employed in the formation of ${\mathrm{SF}}_6$ molecules is

The hybridisation of SF₆ is sp³d² type.

Let us check the electronic configuration of S in different states,

The electronic configuration of sulphur in ground state is [Ne]3s²3p⁴3d⁰ and the electronic configuration of sulphur in excited state is [Ne]3s¹3p³3d²

There are six orbitals involved in hybridisation, namely, 3s, 3p_y, 3p_y, 3p_z, 3dx²-y², 3dz²

It has sp³d² hybridisation due to the presence of vacant d orbitals.