The type of hybridization and magnetic property of the complex [MnCl₆]^3–, respectively, are

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d²sp³, Diamagnetic

sp³d², diamagnetic

d²sp³, Paramagnetic

sp³d², Paramagnetic

answer is D.

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Detailed Solution

[MnCl₆]³⁻ Cl ion exists as a weak field ligand ,4 unpaired electrons are present it forms outer orbital complex ${SP}^{3} d^{2}$ , Paramagnetic due to unpaired electrons.

Hence, correct option is: (D) ${SP}^{3} d^{2}$ ,Paramagnetic

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