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The type of hybridization and number of lone pair(s) of electrons of $Xe$ in ${XeOF}_{4}$ respectively, are

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{sp}^{3} d^{2} and 1

{sp}^{3} d and 2

{sp}^{3} d^{2} and 2

{sp}^{3} d and 1

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detailed solution

Correct option is A

In XeOF₄, Xe is sp³d² hybridised (6 electron pairs) − 5 bond pairs and 1 lone pair.

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The type of hybridization and number of lone pair(s) of electrons of Xe in XeOF4 respectively, are