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Q.

The type of hybridization and number of lone pair(s) of electrons of $Xe$ in ${XeOF}_{4}$ respectively, are

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a

${sp}^{3} d^{2} and 1$

b

${sp}^{3} d and 2$

c

${sp}^{3} d and 1$

d

${sp}^{3} d^{2} and 2$

answer is A.

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Detailed Solution

In XeOF₄, Xe is sp³d² hybridised (6 electron pairs) − 5 bond pairs and 1 lone pair.

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