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Q.

The type of hybridization and number of lone pair(s) of electrons of Xe in XeOF4 respectively, are

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a

sp3d2 and 1

b

sp3d and 2

c

sp3d and 1

d

sp3d2 and 2

answer is A.

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Detailed Solution

In  Xe​OF4​Xe is sp3d2 hybridised (6 electron pairs) − 5 bond pairs and 1 lone pair.

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