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The uncertainty in position of a minute particle of mass 25 gin space is 10^-5 m. The uncertainty in its velocity (in ms^-1) is

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2.1 x 10^-34

0.5 x 10^-34

2.1 x 10^-28

0.5 x 10^-23

answer is C.

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Detailed Solution

$Δu = \frac{h}{4 πm \cdot Δx} = \frac{6 .626 \times 10^{- 34}}{4 \times 3 .14 \times 25 \times 10^{3} \times 10^{5}} = 2 .1 \times 10^{- 28} m / s$

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