The uncertainty in the position of an electron (mass 9.1×10−28g ) moving with a velocity of 3.0×104 cm−1 accurate up to 0.011%,will be

Δx.Δv=h4πm∆v=3.0×104×0.011100=3.3cm/s ∆x=6.625×10-274×3.14×9.11×10-28×3.3=0.175cm

The uncertainty in the position of an electron (mass 9.1×10−28g ) moving with a velocity of 3.0×104 cm−1 accurate up to 0.011%,will be

Δx.Δv=h4πm∆v=3.0×104×0.011100=3.3cm/s ∆x=6.625×10-274×3.14×9.11×10-28×3.3=0.175cm

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The uncertainty in the position of an electron $(mass 9.1 \times 10^{- 28} g)$ moving with a velocity of $3.0 \times 10^{4} {cm}^{- 1}$ accurate up to 0.011%,will be

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3.84 cm

1.92 cm

0.175 cm

7.68 cm

answer is C.

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$Δ x . Δ v = \frac{h}{4 π m}$

$∆ v = 3.0 \times 10^{4} \times \frac{0.011}{100} = 3.3 c m / s ∆ x = \frac{6.625 \times 10^{- 27}}{4 \times 3.14 \times 9.11 \times 10^{- 28} \times 3.3} = 0.175 c m$

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The uncertainty in the position of an electron (mass 9.1×10−28g ) moving with a velocity of 3.0×104 cm−1 accurate up to 0.011%,will be

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The uncertainty in the position of an electron $(mass 9.1 \times 10^{- 28} g)$ moving with a velocity of $3.0 \times 10^{4} {cm}^{- 1}$ accurate up to 0.011%,will be