The unit cell of copper corresponds to a face centered cube of edge length 3.596Å with one copper atom at each lattice point. The calculated density of copper in kg/m³ is ____
[Molar mass of Cu = 63.54g: Avogadro number = 6.022 × 10²³]

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answer is 9076.2.

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Detailed Solution

Given, FCC edge length 3.596Å
We need to find the calculated density of copper in kg/m³.

$\begin{array}{l} d = \frac{Z \times CMM}{N_{A} \times a^{3}} \\ d = \frac{Z 4 \times 63.54 \times 10^{- 3}}{6.022 \times 10^{23} \times {(3.956 \times 10^{- 11})}^{3}} \\ d = 0.9076 \times 104 = 9076.2 kg / m 3 \end{array}$

Therefore, the correct answer 9076.2

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