The unit of length convenient on the atomic scale is known as an angstrom and is denoted by $\stackrel{0}{A}.1\stackrel{0}{A}={10}^{-10}m.$The size of the hydrogen atom is about  $0.5\stackrel{0}{A}$.  The total atomic volume in $m^3$ of a mole of hydrogen atoms would be

Radius of hydrogen atom $\left(r\right)=0.5\stackrel{0}{A}=0.5\times {10}^{-10}m$

Volume of each hydrogen atom $\left(V\right)=\frac{4}{3}\pi r^3$

$=\frac{4}{3}\times 3.14\times {(0.5\times {10}^{-10})}^3$

$=5.234\times {10}^{-31}{m}^3$

Number of atoms in one mole of hydrogen = Avogadro number (N)
$=6.023\times {10}^{23}$

$\therefore$Atomic volume of 1 mole of hydrogen atoms $(V\text{'})$

= Volume of a hydrogen atom ×Number of atoms

$V\text{'}=V\times N$

$5.236\times {10}^{-31}\times 6.023\times {10}^{23}{m}^3$

$=3.152\times {10}^{-7}{m}^3$