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Q.

The unit vector parallel to the resultant of the vectors A=4i^+3j^+6k^andB=i^+3j^8k^  is                     

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a

17(3i^+6j^2k^)

b

149(3i^+6j^2k^)

c

149(3i^6j^+2k^)

d

17(3i^+6j^+2k^)

answer is A.

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Detailed Solution

A¯=4i^+3j^+6k^

B¯=i^+3j^8k^

A¯+B¯=3i^+6j^2k^

Unit vector parallel to A¯+B¯  is

A¯+B¯|A¯+B¯|=3i^+6j^2k^7=17(3i^+6j^2k^)

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