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The unstable nucleus $_{82}^{212} Pb$ decays with $β$ -particle emission, having a half-life of 10 h. From this it follows that the
A : mass number of the product is 212
B : atomic number of the product is 81
C : fraction of the original isotope remaining after 20 h is $\frac{1}{4}$
D : product nucleus formed belongs to same group
Select the correct alternate.

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Only D

A,B and C

B and D

A and C

answer is B.

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Detailed Solution

.once beta particle is emitted atomic number increases by one unit, therefore its group also changes in this case

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