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Q.

The upper end of a wire of radius 4mm and length 100cm is clamped and its other end is twisted through an angle of 30∘ then the angle of shear is

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a

0.012∘

b

0.12∘

c

12∘

d

1.2∘

answer is B.

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Detailed Solution

ϕ=rθl=4×10−3×30 100×10−2=0.12°

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