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The upper end of a wire of diameter 12mm and length 1m is clamped and its other end is twisted through an angle of 30°. The angle of shear is

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0.18°

0.36°

36°

18°

answer is B.

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Detailed Solution

rθ = ℓϕ ⇒ ϕ = rθ / ℓ = (6 mm × 30°) / 1 m = 0.18°

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