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The upper end of the string of a simple pendulum is fixed to a vertical z axis, and set in motion such that the bob moves along a horizontal circular path of radius 2m parallel to the x-y plane. 5m above the origin .The bob has a speed of $3m/s$ The string breaks when the bob is vertically above the x-axis and it lands on the x-y plane at a point (x,y)

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$x=2m$

$x>2m$

$y=3m$

$y=2m$

answer is A, C.

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Detailed Solution

$Δ_{z} = u_{z} t + \frac{1}{2} a_{z} t^{2}$

$5 = 0 + \frac{1}{2} \times 10 t^{2} \Rightarrow t = 1 \sec$

$Δ_{x} = u_{x} + \frac{1}{2} a_{x} t^{2}$

$x_{f} - 2 = 0 + 0 \Rightarrow x_{f} = 2 m$

$Δ_{y} = u_{y} t + \frac{1}{2} a y t^{2}$

$y_{f} - 0 = 3 \times 1 + 0 \Rightarrow y_{f} = 3 m$

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