The upper half an inclined plane of inclination θ is perfectly smooth while the lower half is rough. A block starting from rest at the top of the plane will again come to rest at the bottom. The coefficient of friction between the block and the lower half of the plane is given by

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µ = 1/tanθ

µ = tanθ

µ = 2/tanθ

µ = 2tanθ

answer is A.

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Detailed Solution

For the upper half acceleration = gsinθ and v² = 0 + 2.gsinθ.l/2.....(1)
For the lower half retardation a = g(µsinθ - sinθ) and 0 = v² - 2.a.l/2....(2)
From (1) and (2): 2gsinθ.l/2 = 2.g(µcosθ - sinθ).l/2 ⇒ µ = 2tanθ.

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