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Q.

The $v^{2} - s$ graph are given for particles. Find the acceleration of the particle at s=0 is $2 \times 10^{- x} m / \sec^{2}$ . The value of ‘x’ is

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Detailed Solution

$a_{2} = \frac{1}{2} \frac{d (v^{2})}{d t} = - \frac{2}{5}$

$a_{2} = - 0.4 m / s^{2}$

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The v2−s graph are given for particles. Find the acceleration of the particle at s=0 is 2×10−x m/sec2 . The value of ‘x’ is