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Q.

The value of 1 main scale division of vernier calipers reads 1mm and 10 divisions of vernier scale is equal to 9 divisions on main scale. When the two jaws of the instrument touch each other, the zero of the vernier lies to the right of zero of the main scale and its fourth division coincides with a main scale division. When a spherical bob is tightly placed between the two jaws, the zero of the vernier scale lies in between 4.1 cm and 4.2 cm and 6th vernier division coincides with a main scale division. The diameter of the bob will be _____ $\times 10^{- 2} c m .$

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answer is 412.

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Detailed Solution

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$L C = \frac{1 m m}{10} = 0.1 m m = 0.01 c m$

Zero error $= + 4$

Zero correction $= - 4$

Diameter $D = 4.1 c m + (6 - 4) \times 0.01 c m = 4.12 c m = 412 \times 10^{- 2} c m$

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The value of 1 main scale division of vernier calipers reads 1mm and 10 divisions of vernier scale is equal to 9 divisions on main scale. When the two jaws of the instrument touch each other, the zero of the vernier lies to the right of zero of the main scale and its fourth division coincides with a main scale division. When a spherical bob is tightly placed between the two jaws, the zero of the vernier scale lies in between 4.1 cm and 4.2 cm and 6th vernier division coincides with a main scale division. The diameter of the bob will be _____×10−2cm.