The value of 2 sin $\left(12°\right)$ $-$sin$\left(72°\right)$ is :

$$\begin{gathered} \sin 12°+\sin 12°-\sin 72° \\ =\sin 12°-2\cos 42°\sin 30° \boxed{\sin C-\sin D=2\cos \frac{C+D}{2}\sin \frac{C-D}{2}} \\ =\sin 12°-\sin 48° \\ =-2\cos 30°\sin 18° \\ =-2\times \frac{\sqrt{3}}{2}\times \frac{\sqrt{5}-1}{4} \\ =\frac{\sqrt{3}}{4}(1-\sqrt{5}) \\ \mathrm{Option} \left(\mathrm{D}\right) \mathrm{is} \mathrm{Correct} \end{gathered}$$