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Q.

The value of 
 (300)(3010)(301)(3011)+(302)(3012)......+(3020)(3030)=
 

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a

 60C30

b

 60C20

c

 30C10

d

 40C30

answer is B.

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Detailed Solution

 (1x)30=C0   30x030C1x1+30C2x2+........+(1)30C30x30 (x+1)30=30c0x30+30c1x29+.................+30c30
 
Multiplying (1) and (2) and  equating the coefficient of  x20 on both sides, we get required     sum is equal to coefficient of  x20  in  (1x2)30, which is given by C10   30.  
 

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