Book Online Demo

Check Your IQ

Try Test

Courses

Offline Centres

The value of ${[{(3^{1})}^{2}]}^{- 1}$ is

see full answer

Talk to JEE/NEET 2025 Toppers - Learn What Actually Works!

Real Strategies. Real People. Real Success Stories - Just 1 call away

An Intiative by Sri Chaitanya

9

- 9

- 0.1111

0.1111

answer is D.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

We have to find the value of

{[{(3^{1})}^{2}]}^{- 1} .

We know,

(∵ (a^{m})^{n} = a^{mn}

) , where m and n are integers and a being any real number.
Also

a^{- m} = (\frac{1}{a^{m}})

, where m is an integer and a being any real number.
Solving,

{[{(3^{1})}^{2}]}^{- 1} = \frac{1}{{(3^{1})}^{2}}

\Rightarrow {[{(3^{1})}^{2}]}^{- 1} = \frac{1}{3^{2}}

\Rightarrow

{[{(3^{1})}^{2}]}^{- 1} = \frac{1}{9}

\Rightarrow

{[{(3^{1})}^{2}]}^{- 1} = 0.1111

Therefore, the value of

{[{(3^{1})}^{2}]}^{- 1}

= 0.1111

.
Hence, option 4 is correct.

Watch 3-min video & get full concept clarity

JEE

NEET

Foundation JEE

Foundation NEET

CBSE