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Q.

The value of acceleration due to gravity on the surface of earth is x. At altitude of ‘h’ from the surface of earth, its value is y. If ‘R’ is the radius of earth, then the value of h is

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a

(\sqrt{\frac{x}{y}} - 1) R

b

\sqrt{\frac{y}{x}} R

c

(\sqrt{\frac{y}{x}} - 1) R

d

\sqrt{\frac{x}{y}} R

answer is A.

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Detailed Solution

g_{h} = g {[\frac{R}{R + h}]}^{2}

$y = x {[\frac{R}{R + h}]}^{2} \Rightarrow h = R [\sqrt{\frac{x}{y}} - 1]$

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